Login
Register
Cbse
Q&A
Questions
Unanswered
Ask a Question
Example1
Example1
Solution of below question Solution of below question Solution of below question Solution of below question Solution of below question Solution of below question
0
votes
$$\displaystyle x = \frac{ - b \pm \displaystyle\sqrt {b^2 - 4ac} }{2a}\ {\text{when}}\ {ax^2 + bx + c = 0}$$
asked
Jun 17
in
Physics
by
harbindra
(
120
points)
edited
Jun 18
by
harbindra
Your answer
Your name to display (optional):
Email me at this address if my answer is selected or commented on:
Email me if my answer is selected or commented on
Privacy: Your email address will only be used for sending these notifications.
0
Answers
...